If the lines 3y 4x - 1 and qy x 3 are parallel ... - JAMB Mathematics 2007 Question
If the lines 3y = 4x - 1 and qy = x + 3 are parallel to each other, the value of q is
A
-\(\frac{4}{3}\)
B
-\(\frac{3}{4}\)
C
\(\frac{3}{4}\)
D
\(\frac{4}{3}\)
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Correct Option: C
L1(\Rightarrow) 3Y = 4X - 1
Y = (\frac{4}{3})X - (\frac{1}{3})
therefore m1 = (\frac{4}{3})
L2(\Rightarrow) qy = x + 3
y = (\frac{1}{q})X + (\frac{3}{q})
therefore, m2 = (\frac{1}{q})
For parallel lines, m1 = m2; (\frac{4}{3}) = (\frac{1}{q})
therefore q = (\frac{3}{4})
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